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3x-0.75x^2=0
a = -0.75; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-0.75)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-0.75}=\frac{-6}{-1.5} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-0.75}=\frac{0}{-1.5} =0 $
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